Base | Representation |
---|---|
bin | 100001000001011001000110… |
… | …110100000100110111100011 |
3 | 201001012222010212220120110111 |
4 | 201001121012310010313203 |
5 | 123013432010311002431 |
6 | 1232514144155312151 |
7 | 42406415553250111 |
oct | 4101310664046743 |
9 | 631188125816414 |
10 | 145231212203491 |
11 | 423032361343a7 |
12 | 1435694714b657 |
13 | 6306324363b9b |
14 | 27c132a188ab1 |
15 | 11bcbe54077b1 |
hex | 841646d04de3 |
145231212203491 has 2 divisors, whose sum is σ = 145231212203492. Its totient is φ = 145231212203490.
The previous prime is 145231212203431. The next prime is 145231212203521. The reversal of 145231212203491 is 194302212132541.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145231212203491 is a prime.
It is not a weakly prime, because it can be changed into another prime (145231212203431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72615606101745 + 72615606101746.
It is an arithmetic number, because the mean of its divisors is an integer number (72615606101746).
Almost surely, 2145231212203491 is an apocalyptic number.
145231212203491 is a deficient number, since it is larger than the sum of its proper divisors (1).
145231212203491 is an equidigital number, since it uses as much as digits as its factorization.
145231212203491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 40.
The spelling of 145231212203491 in words is "one hundred forty-five trillion, two hundred thirty-one billion, two hundred twelve million, two hundred three thousand, four hundred ninety-one".
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