145240341131 has 2 divisors, whose sum is σ = 145240341132. Its totient is φ = 145240341130.

The previous prime is 145240341053. The next prime is 145240341133. The reversal of 145240341131 is 131143042541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145240341131 - 2¹⁸ = 145240078987 is a prime.

It is a super-2 number, since 2×145240341131² (a number of 23 digits) contains 22 as substring.

Together with 145240341133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 145240341094 and 145240341103.

It is not a weakly prime, because it can be changed into another prime (145240341133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72620170565 + 72620170566.

It is an arithmetic number, because the mean of its divisors is an integer number (72620170566).

Almost surely, 2^145240341131 is an apocalyptic number.

145240341131 is a deficient number, since it is larger than the sum of its proper divisors (1).

145240341131 is an equidigital number, since it uses as much as digits as its factorization.

145240341131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 145240341131 its reverse (131143042541), we get a palindrome (276383383672).

The spelling of 145240341131 in words is "one hundred forty-five billion, two hundred forty million, three hundred forty-one thousand, one hundred thirty-one".