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145241351251 is a prime number
BaseRepresentation
bin1000011101000100001…
…1110010010001010011
3111212220010020002222121
42013101003302101103
54334423241220001
6150420054115111
713331134054513
oct2072103622123
9455803202877
10145241351251
1156661a57997
122419504ba97
1310908725779
14705b797843
153ba0e4e6a1
hex21d10f2453

145241351251 has 2 divisors, whose sum is σ = 145241351252. Its totient is φ = 145241351250.

The previous prime is 145241351197. The next prime is 145241351399. The reversal of 145241351251 is 152153142541.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 145241351251 - 213 = 145241343059 is a prime.

It is a super-2 number, since 2×1452413512512 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145241331251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72620675625 + 72620675626.

It is an arithmetic number, because the mean of its divisors is an integer number (72620675626).

Almost surely, 2145241351251 is an apocalyptic number.

145241351251 is a deficient number, since it is larger than the sum of its proper divisors (1).

145241351251 is an equidigital number, since it uses as much as digits as its factorization.

145241351251 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24000, while the sum is 34.

Adding to 145241351251 its reverse (152153142541), we get a palindrome (297394493792).

The spelling of 145241351251 in words is "one hundred forty-five billion, two hundred forty-one million, three hundred fifty-one thousand, two hundred fifty-one".