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14525260117997 is a prime number
BaseRepresentation
bin1101001101011110110011…
…1110000011011111101101
31220102121020100111121121212
43103113230332003133231
53400440213042233442
650520451250204205
73026262325604006
oct323275476033755
956377210447555
1014525260117997
1146a0145733662
121767114283665
138149594810b5
143830523ca1ad
151a2c7e485a82
hexd35ecf837ed

14525260117997 has 2 divisors, whose sum is σ = 14525260117998. Its totient is φ = 14525260117996.

The previous prime is 14525260117987. The next prime is 14525260118003. The reversal of 14525260117997 is 79971106252541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9989322826921 + 4535937291076 = 3160589^2 + 2129774^2 .

It is a cyclic number.

It is not a de Polignac number, because 14525260117997 - 214 = 14525260101613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14525260117987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7262630058998 + 7262630058999.

It is an arithmetic number, because the mean of its divisors is an integer number (7262630058999).

Almost surely, 214525260117997 is an apocalyptic number.

It is an amenable number.

14525260117997 is a deficient number, since it is larger than the sum of its proper divisors (1).

14525260117997 is an equidigital number, since it uses as much as digits as its factorization.

14525260117997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9525600, while the sum is 59.

The spelling of 14525260117997 in words is "fourteen trillion, five hundred twenty-five billion, two hundred sixty million, one hundred seventeen thousand, nine hundred ninety-seven".