Base | Representation |
---|---|
bin | 11011000011100100… |
… | …11001000011110001 |
3 | 1101111022021221100202 |
4 | 31201302121003301 |
5 | 214222012023211 |
6 | 10401203524545 |
7 | 1022645504255 |
oct | 154162310361 |
9 | 41438257322 |
10 | 14525501681 |
11 | 61842a3449 |
12 | 2994689755 |
13 | 14a6452612 |
14 | 9bb1ca265 |
15 | 5a033753b |
hex | 361c990f1 |
14525501681 has 2 divisors, whose sum is σ = 14525501682. Its totient is φ = 14525501680.
The previous prime is 14525501651. The next prime is 14525501741. The reversal of 14525501681 is 18610552541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8834308081 + 5691193600 = 93991^2 + 75440^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14525501681 is a prime.
It is a super-2 number, since 2×145255016812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14525501651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7262750840 + 7262750841.
It is an arithmetic number, because the mean of its divisors is an integer number (7262750841).
Almost surely, 214525501681 is an apocalyptic number.
It is an amenable number.
14525501681 is a deficient number, since it is larger than the sum of its proper divisors (1).
14525501681 is an equidigital number, since it uses as much as digits as its factorization.
14525501681 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48000, while the sum is 38.
The spelling of 14525501681 in words is "fourteen billion, five hundred twenty-five million, five hundred one thousand, six hundred eighty-one".
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