Base | Representation |
---|---|
bin | 1000011101001001011… |
… | …1100001110110101111 |
3 | 111212221122112102122111 |
4 | 2013102113201312233 |
5 | 4334444401212421 |
6 | 150422200424451 |
7 | 13331521466152 |
oct | 2072227416657 |
9 | 455848472574 |
10 | 145263304111 |
11 | 56673391452 |
12 | 241a0478127 |
13 | 10910140a23 |
14 | 706066dc99 |
15 | 3ba2d38ee1 |
hex | 21d25e1daf |
145263304111 has 4 divisors (see below), whose sum is σ = 146620905192. Its totient is φ = 143905703032.
The previous prime is 145263304103. The next prime is 145263304133. The reversal of 145263304111 is 111403362541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 145263304111 - 23 = 145263304103 is a prime.
It is a super-2 number, since 2×1452633041112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145263304141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 678800380 + ... + 678800593.
It is an arithmetic number, because the mean of its divisors is an integer number (36655226298).
Almost surely, 2145263304111 is an apocalyptic number.
145263304111 is a deficient number, since it is larger than the sum of its proper divisors (1357601081).
145263304111 is a wasteful number, since it uses less digits than its factorization.
145263304111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1357601080.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 145263304111 its reverse (111403362541), we get a palindrome (256666666652).
The spelling of 145263304111 in words is "one hundred forty-five billion, two hundred sixty-three million, three hundred four thousand, one hundred eleven".
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