145263304133 has 2 divisors, whose sum is σ = 145263304134. Its totient is φ = 145263304132.

The previous prime is 145263304103. The next prime is 145263304141. The reversal of 145263304133 is 331403362541.

145263304133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83728052164 + 61535251969 = 289358^2 + 248063^2 .

It is a cyclic number.

It is not a de Polignac number, because 145263304133 - 2¹⁰ = 145263303109 is a prime.

It is a super-2 number, since 2×145263304133² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145263304093 and 145263304102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145263304103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72631652066 + 72631652067.

It is an arithmetic number, because the mean of its divisors is an integer number (72631652067).

Almost surely, 2^145263304133 is an apocalyptic number.

It is an amenable number.

145263304133 is a deficient number, since it is larger than the sum of its proper divisors (1).

145263304133 is an equidigital number, since it uses as much as digits as its factorization.

145263304133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 145263304133 its reverse (331403362541), we get a palindrome (476666666674).

The spelling of 145263304133 in words is "one hundred forty-five billion, two hundred sixty-three million, three hundred four thousand, one hundred thirty-three".