Base | Representation |
---|---|
bin | 1000011101001001011… |
… | …1100001110110100111 |
3 | 111212221122112102122012 |
4 | 2013102113201312213 |
5 | 4334444401212403 |
6 | 150422200424435 |
7 | 13331521466141 |
oct | 2072227416647 |
9 | 455848472565 |
10 | 145263304103 |
11 | 56673391445 |
12 | 241a047811b |
13 | 10910140a18 |
14 | 706066dc91 |
15 | 3ba2d38ed8 |
hex | 21d25e1da7 |
145263304103 has 2 divisors, whose sum is σ = 145263304104. Its totient is φ = 145263304102.
The previous prime is 145263304093. The next prime is 145263304133. The reversal of 145263304103 is 301403362541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145263304103 - 216 = 145263238567 is a prime.
It is a super-2 number, since 2×1452633041032 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 145263304103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145263304133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72631652051 + 72631652052.
It is an arithmetic number, because the mean of its divisors is an integer number (72631652052).
Almost surely, 2145263304103 is an apocalyptic number.
145263304103 is a deficient number, since it is larger than the sum of its proper divisors (1).
145263304103 is an equidigital number, since it uses as much as digits as its factorization.
145263304103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 145263304103 its reverse (301403362541), we get a palindrome (446666666644).
The spelling of 145263304103 in words is "one hundred forty-five billion, two hundred sixty-three million, three hundred four thousand, one hundred three".
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