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145273183331 is a prime number
BaseRepresentation
bin1000011101001011110…
…1001101110001100011
3111212222100010100101112
42013102331031301203
54340004413331311
6150423152253535
713332001453433
oct2072275156143
9455870110345
10145273183331
1156678a198a1
12241a38412ab
13109121bc613
147061ac22c3
153ba3b3b28b
hex21d2f4dc63

145273183331 has 2 divisors, whose sum is σ = 145273183332. Its totient is φ = 145273183330.

The previous prime is 145273183313. The next prime is 145273183333. The reversal of 145273183331 is 133381372541.

Together with previous prime (145273183313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145273183331 - 226 = 145206074467 is a prime.

It is a super-2 number, since 2×1452731833312 (a number of 23 digits) contains 22 as substring.

Together with 145273183333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (145273183333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72636591665 + 72636591666.

It is an arithmetic number, because the mean of its divisors is an integer number (72636591666).

Almost surely, 2145273183331 is an apocalyptic number.

145273183331 is a deficient number, since it is larger than the sum of its proper divisors (1).

145273183331 is an equidigital number, since it uses as much as digits as its factorization.

145273183331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 181440, while the sum is 41.

The spelling of 145273183331 in words is "one hundred forty-five billion, two hundred seventy-three million, one hundred eighty-three thousand, three hundred thirty-one".