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145288005011 is a prime number
BaseRepresentation
bin1000011101001111010…
…1110000010110010011
3111220000101000100220122
42013103311300112103
54340022212130021
6150424442100455
713332241444352
oct2072365602623
9456011010818
10145288005011
1156686322616
12241a87aa72b
13109152aba46
147063a5d999
153ba50b7bab
hex21d3d70593

145288005011 has 2 divisors, whose sum is σ = 145288005012. Its totient is φ = 145288005010.

The previous prime is 145288004929. The next prime is 145288005013. The reversal of 145288005011 is 110500882541.

145288005011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145288005011 - 214 = 145287988627 is a prime.

It is a super-2 number, since 2×1452880050112 (a number of 23 digits) contains 22 as substring.

Together with 145288005013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (145288005013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72644002505 + 72644002506.

It is an arithmetic number, because the mean of its divisors is an integer number (72644002506).

Almost surely, 2145288005011 is an apocalyptic number.

145288005011 is a deficient number, since it is larger than the sum of its proper divisors (1).

145288005011 is an equidigital number, since it uses as much as digits as its factorization.

145288005011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12800, while the sum is 35.

Adding to 145288005011 its reverse (110500882541), we get a palindrome (255788887552).

The spelling of 145288005011 in words is "one hundred forty-five billion, two hundred eighty-eight million, five thousand, eleven".