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1453040301121 is a prime number
BaseRepresentation
bin10101001001001111111…
…100110111010001000001
312010220112212200021011221
4111021033330313101001
5142301311304113441
63031303440235041
7206656456526323
oct25111774672101
95126485607157
101453040301121
1151025a4075a2
121b573830ba81
13a70374cba36
1450482a33613
1527be48a98d1
hex1524ff37441

1453040301121 has 2 divisors, whose sum is σ = 1453040301122. Its totient is φ = 1453040301120.

The previous prime is 1453040301103. The next prime is 1453040301221. The reversal of 1453040301121 is 1211030403541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 963075300496 + 489965000625 = 981364^2 + 699975^2 .

It is a cyclic number.

It is not a de Polignac number, because 1453040301121 - 29 = 1453040300609 is a prime.

It is a super-2 number, since 2×14530403011212 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1453040301221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726520150560 + 726520150561.

It is an arithmetic number, because the mean of its divisors is an integer number (726520150561).

Almost surely, 21453040301121 is an apocalyptic number.

It is an amenable number.

1453040301121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1453040301121 is an equidigital number, since it uses as much as digits as its factorization.

1453040301121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1453040301121 its reverse (1211030403541), we get a palindrome (2664070704662).

The spelling of 1453040301121 in words is "one trillion, four hundred fifty-three billion, forty million, three hundred one thousand, one hundred twenty-one".