1453102146131 has 2 divisors, whose sum is σ = 1453102146132. Its totient is φ = 1453102146130.

The previous prime is 1453102146121. The next prime is 1453102146143. The reversal of 1453102146131 is 1316412013541.

It is a weak prime.

It is an emirp because it is prime and its reverse (1316412013541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1453102146131 is a prime.

It is a super-2 number, since 2×1453102146131² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1453102146121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726551073065 + 726551073066.

It is an arithmetic number, because the mean of its divisors is an integer number (726551073066).

Almost surely, 2^{1453102146131} is an apocalyptic number.

1453102146131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1453102146131 is an equidigital number, since it uses as much as digits as its factorization.

1453102146131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 1453102146131 its reverse (1316412013541), we get a palindrome (2769514159672).

The spelling of 1453102146131 in words is "one trillion, four hundred fifty-three billion, one hundred two million, one hundred forty-six thousand, one hundred thirty-one".