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1453253002231 is a prime number
BaseRepresentation
bin10101001001011100101…
…000010000001111110111
312010221002200220121020211
4111021130220100033313
5142302230232032411
63031340515210251
7206664651463222
oct25113450201767
95127080817224
101453253002231
11510359485038
121b57975a6987
13a706c5b2194
14504a2da05b9
1527c083c2221
hex1525ca103f7

1453253002231 has 2 divisors, whose sum is σ = 1453253002232. Its totient is φ = 1453253002230.

The previous prime is 1453253002219. The next prime is 1453253002273. The reversal of 1453253002231 is 1322003523541.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1453253002231 is a prime.

It is a super-3 number, since 3×14532530022313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1453253002193 and 1453253002202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1453253002211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726626501115 + 726626501116.

It is an arithmetic number, because the mean of its divisors is an integer number (726626501116).

Almost surely, 21453253002231 is an apocalyptic number.

1453253002231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1453253002231 is an equidigital number, since it uses as much as digits as its factorization.

1453253002231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 1453253002231 its reverse (1322003523541), we get a palindrome (2775256525772).

The spelling of 1453253002231 in words is "one trillion, four hundred fifty-three billion, two hundred fifty-three million, two thousand, two hundred thirty-one".