Base | Representation |
---|---|
bin | 11011000100100101… |
… | …11110010000010001 |
3 | 1101111220100212100121 |
4 | 31202102332100101 |
5 | 214231203331031 |
6 | 10402110550241 |
7 | 1023111216106 |
oct | 154222762021 |
9 | 41456325317 |
10 | 14534042641 |
11 | 61890a7398 |
12 | 2997508381 |
13 | 14a8153041 |
14 | 9bc3b0aad |
15 | 5a0e73011 |
hex | 3624be411 |
14534042641 has 2 divisors, whose sum is σ = 14534042642. Its totient is φ = 14534042640.
The previous prime is 14534042587. The next prime is 14534042659. The reversal of 14534042641 is 14624043541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14472090000 + 61952641 = 120300^2 + 7871^2 .
It is a cyclic number.
It is not a de Polignac number, because 14534042641 - 219 = 14533518353 is a prime.
It is a super-2 number, since 2×145340426412 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14534042597 and 14534042606.
It is not a weakly prime, because it can be changed into another prime (14534042681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7267021320 + 7267021321.
It is an arithmetic number, because the mean of its divisors is an integer number (7267021321).
Almost surely, 214534042641 is an apocalyptic number.
It is an amenable number.
14534042641 is a deficient number, since it is larger than the sum of its proper divisors (1).
14534042641 is an equidigital number, since it uses as much as digits as its factorization.
14534042641 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 34.
The spelling of 14534042641 in words is "fourteen billion, five hundred thirty-four million, forty-two thousand, six hundred forty-one".
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