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14534113361 is a prime number
BaseRepresentation
bin11011000100100110…
…01111100001010001
31101111220111110100212
431202103033201101
5214231213111421
610402112253505
71023111632225
oct154223174121
941456443325
1014534113361
116189145539
122997541295
1314a81792a1
149bc3cc785
155a0e88e5b
hex3624cf851

14534113361 has 2 divisors, whose sum is σ = 14534113362. Its totient is φ = 14534113360.

The previous prime is 14534113313. The next prime is 14534113369. The reversal of 14534113361 is 16331143541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14413443136 + 120670225 = 120056^2 + 10985^2 .

It is an emirp because it is prime and its reverse (16331143541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14534113361 is a prime.

It is a super-2 number, since 2×145341133612 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14534113369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7267056680 + 7267056681.

It is an arithmetic number, because the mean of its divisors is an integer number (7267056681).

Almost surely, 214534113361 is an apocalyptic number.

It is an amenable number.

14534113361 is a deficient number, since it is larger than the sum of its proper divisors (1).

14534113361 is an equidigital number, since it uses as much as digits as its factorization.

14534113361 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960, while the sum is 32.

The spelling of 14534113361 in words is "fourteen billion, five hundred thirty-four million, one hundred thirteen thousand, three hundred sixty-one".