Base | Representation |
---|---|
bin | 10101001001100111010… |
… | …100010111111010100011 |
3 | 12010221120012100220121021 |
4 | 111021213110113322203 |
5 | 142303112134341011 |
6 | 3031410403110311 |
7 | 210002260023232 |
oct | 25114724277243 |
9 | 5127505326537 |
10 | 1453432340131 |
11 | 510440735282 |
12 | 1b5827672397 |
13 | a709a7b3895 |
14 | 504bcb24b19 |
15 | 27c18ee9471 |
hex | 15267517ea3 |
1453432340131 has 2 divisors, whose sum is σ = 1453432340132. Its totient is φ = 1453432340130.
The previous prime is 1453432340089. The next prime is 1453432340141. The reversal of 1453432340131 is 1310432343541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1453432340131 - 215 = 1453432307363 is a prime.
It is a super-2 number, since 2×14534323401312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1453432340141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726716170065 + 726716170066.
It is an arithmetic number, because the mean of its divisors is an integer number (726716170066).
Almost surely, 21453432340131 is an apocalyptic number.
1453432340131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1453432340131 is an equidigital number, since it uses as much as digits as its factorization.
1453432340131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 1453432340131 its reverse (1310432343541), we get a palindrome (2763864683672).
The spelling of 1453432340131 in words is "one trillion, four hundred fifty-three billion, four hundred thirty-two million, three hundred forty thousand, one hundred thirty-one".
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