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145343351444 = 22191912412519
BaseRepresentation
bin1000011101011100100…
…0111000101010010100
3111220011020011020221112
42013113020320222110
54340130344221234
6150434140234152
713333513050254
oct2072710705224
9456136136845
10145343351444
1156704595175
122420323b958
13109238b9805
14706b149964
153ba9d9bace
hex21d7238a94

145343351444 has 12 divisors (see below), whose sum is σ = 267737752800. Its totient is φ = 68846850648.

The previous prime is 145343351443. The next prime is 145343351449. The reversal of 145343351444 is 444153343541.

It is a super-2 number, since 2×1453433514442 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145343351443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 956206184 + ... + 956206335.

It is an arithmetic number, because the mean of its divisors is an integer number (22311479400).

Almost surely, 2145343351444 is an apocalyptic number.

It is an amenable number.

145343351444 is a deficient number, since it is larger than the sum of its proper divisors (122394401356).

145343351444 is a wasteful number, since it uses less digits than its factorization.

145343351444 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1912412542 (or 1912412540 counting only the distinct ones).

The product of its digits is 691200, while the sum is 41.

Adding to 145343351444 its reverse (444153343541), we get a palindrome (589496694985).

The spelling of 145343351444 in words is "one hundred forty-five billion, three hundred forty-three million, three hundred fifty-one thousand, four hundred forty-four".

Divisors: 1 2 4 19 38 76 1912412519 3824825038 7649650076 36335837861 72671675722 145343351444