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145344435433 is a prime number
BaseRepresentation
bin1000011101011100110…
…1000001010011101001
3111220011022012022220021
42013113031001103221
54340131133413213
6150434215400441
713333525213501
oct2072715012351
9456138168807
10145344435433
115670516562a
1224203683121
1310923ba9022
14706b34ca01
153baa012d8d
hex21d73414e9

145344435433 has 2 divisors, whose sum is σ = 145344435434. Its totient is φ = 145344435432.

The previous prime is 145344435427. The next prime is 145344435437. The reversal of 145344435433 is 334534443541.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129350280409 + 15994155024 = 359653^2 + 126468^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145344435433 is a prime.

It is a super-2 number, since 2×1453444354332 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 145344435433.

It is not a weakly prime, because it can be changed into another prime (145344435437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72672217716 + 72672217717.

It is an arithmetic number, because the mean of its divisors is an integer number (72672217717).

Almost surely, 2145344435433 is an apocalyptic number.

It is an amenable number.

145344435433 is a deficient number, since it is larger than the sum of its proper divisors (1).

145344435433 is an equidigital number, since it uses as much as digits as its factorization.

145344435433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2073600, while the sum is 43.

Adding to 145344435433 its reverse (334534443541), we get a palindrome (479878878974).

The spelling of 145344435433 in words is "one hundred forty-five billion, three hundred forty-four million, four hundred thirty-five thousand, four hundred thirty-three".