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14537305051 is a prime number
BaseRepresentation
bin11011000100111110…
…11010101111011011
31101112010111121112121
431202133122233123
5214233022230201
610402304522111
71023151024363
oct154237325733
941463447477
1014537305051
11618aa254a5
122998620337
1314a8a25c69
149bc9bd9a3
155a13b99a1
hex3627dabdb

14537305051 has 2 divisors, whose sum is σ = 14537305052. Its totient is φ = 14537305050.

The previous prime is 14537305033. The next prime is 14537305067. The reversal of 14537305051 is 15050373541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14537305051 - 27 = 14537304923 is a prime.

It is a super-2 number, since 2×145373050512 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14537304998 and 14537305016.

It is not a weakly prime, because it can be changed into another prime (14537305351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7268652525 + 7268652526.

It is an arithmetic number, because the mean of its divisors is an integer number (7268652526).

Almost surely, 214537305051 is an apocalyptic number.

14537305051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14537305051 is an equidigital number, since it uses as much as digits as its factorization.

14537305051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31500, while the sum is 34.

Adding to 14537305051 its reverse (15050373541), we get a palindrome (29587678592).

The spelling of 14537305051 in words is "fourteen billion, five hundred thirty-seven million, three hundred five thousand, fifty-one".