Search a number
-
+
145381709113 is a prime number
BaseRepresentation
bin1000011101100101101…
…1001101010100111001
3111220020220100000202221
42013121123031110321
54340220204142423
6150442030324041
713334460065224
oct2073133152471
9456226300687
10145381709113
1156724203923
1224214059621
131092b829964
1470722925bb
153bad426e5d
hex21d96cd539

145381709113 has 2 divisors, whose sum is σ = 145381709114. Its totient is φ = 145381709112.

The previous prime is 145381709111. The next prime is 145381709147. The reversal of 145381709113 is 311907183541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123729469504 + 21652239609 = 351752^2 + 147147^2 .

It is a cyclic number.

It is not a de Polignac number, because 145381709113 - 21 = 145381709111 is a prime.

It is a super-2 number, since 2×1453817091132 (a number of 23 digits) contains 22 as substring.

Together with 145381709111, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 145381709113.

It is not a weakly prime, because it can be changed into another prime (145381709111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72690854556 + 72690854557.

It is an arithmetic number, because the mean of its divisors is an integer number (72690854557).

Almost surely, 2145381709113 is an apocalyptic number.

It is an amenable number.

145381709113 is a deficient number, since it is larger than the sum of its proper divisors (1).

145381709113 is an equidigital number, since it uses as much as digits as its factorization.

145381709113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 43.

The spelling of 145381709113 in words is "one hundred forty-five billion, three hundred eighty-one million, seven hundred nine thousand, one hundred thirteen".