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14538687350413 is a prime number
BaseRepresentation
bin1101001110010000110101…
…0010111000011010001101
31220110212220010012200210011
43103210031102320122031
53401200212430203123
650530551502313221
73030246140314132
oct323441522703215
956425803180704
1014538687350413
1146a5905a94056
121769840b88811
13815cb920a735
143839677a8589
151a32b8179e0d
hexd390d4b868d

14538687350413 has 2 divisors, whose sum is σ = 14538687350414. Its totient is φ = 14538687350412.

The previous prime is 14538687350401. The next prime is 14538687350503. The reversal of 14538687350413 is 31405378683541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8764364858089 + 5774322492324 = 2960467^2 + 2402982^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14538687350413 is a prime.

It is a super-3 number, since 3×145386873504133 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14538687350713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7269343675206 + 7269343675207.

It is an arithmetic number, because the mean of its divisors is an integer number (7269343675207).

Almost surely, 214538687350413 is an apocalyptic number.

It is an amenable number.

14538687350413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14538687350413 is an equidigital number, since it uses as much as digits as its factorization.

14538687350413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 29030400, while the sum is 58.

The spelling of 14538687350413 in words is "fourteen trillion, five hundred thirty-eight billion, six hundred eighty-seven million, three hundred fifty thousand, four hundred thirteen".