14540040233 has 2 divisors, whose sum is σ = 14540040234. Its totient is φ = 14540040232.

The previous prime is 14540040227. The next prime is 14540040239. The reversal of 14540040233 is 33204004541.

It is a balanced prime because it is at equal distance from previous prime (14540040227) and next prime (14540040239).

It can be written as a sum of positive squares in only one way, i.e., 12444964249 + 2095075984 = 111557^2 + 45772^2 .

It is an emirp because it is prime and its reverse (33204004541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14540040233 is a prime.

It is a super-3 number, since 3×14540040233³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14540040239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270020116 + 7270020117.

It is an arithmetic number, because the mean of its divisors is an integer number (7270020117).

Almost surely, 2^14540040233 is an apocalyptic number.

It is an amenable number.

14540040233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540040233 is an equidigital number, since it uses as much as digits as its factorization.

14540040233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 26.

Adding to 14540040233 its reverse (33204004541), we get a palindrome (47744044774).

The spelling of 14540040233 in words is "fourteen billion, five hundred forty million, forty thousand, two hundred thirty-three".