Base | Representation |
---|---|
bin | 11011000101010100… |
… | …00101111010010001 |
3 | 1101112022202210000221 |
4 | 31202222011322101 |
5 | 214234231301223 |
6 | 10402444513041 |
7 | 1023213560521 |
oct | 154252057221 |
9 | 41468683027 |
10 | 14540103313 |
11 | 619156690a |
12 | 299954b781 |
13 | 14a9495838 |
14 | 9bd10b681 |
15 | 5a176db5d |
hex | 362a85e91 |
14540103313 has 2 divisors, whose sum is σ = 14540103314. Its totient is φ = 14540103312.
The previous prime is 14540103271. The next prime is 14540103323. The reversal of 14540103313 is 31330104541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13790274624 + 749828689 = 117432^2 + 27383^2 .
It is an emirp because it is prime and its reverse (31330104541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14540103313 - 217 = 14539972241 is a prime.
It is a super-2 number, since 2×145401033132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14540103323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270051656 + 7270051657.
It is an arithmetic number, because the mean of its divisors is an integer number (7270051657).
Almost surely, 214540103313 is an apocalyptic number.
It is an amenable number.
14540103313 is a deficient number, since it is larger than the sum of its proper divisors (1).
14540103313 is an equidigital number, since it uses as much as digits as its factorization.
14540103313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 14540103313 its reverse (31330104541), we get a palindrome (45870207854).
The spelling of 14540103313 in words is "fourteen billion, five hundred forty million, one hundred three thousand, three hundred thirteen".
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