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145402230433 is a prime number
BaseRepresentation
bin1000011101101010100…
…1011111011010100001
3111220022022221121201211
42013122221133122201
54340240432333213
6150444042230121
713335126365155
oct2073251373241
9456268847654
10145402230433
115673484a899
122421aab5341
1310932b63455
147074cb5065
153bb012c53d
hex21daa5f6a1

145402230433 has 2 divisors, whose sum is σ = 145402230434. Its totient is φ = 145402230432.

The previous prime is 145402230427. The next prime is 145402230497. The reversal of 145402230433 is 334032204541.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89035398544 + 56366831889 = 298388^2 + 237417^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145402230433 is a prime.

It is a super-2 number, since 2×1454022304332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145402230395 and 145402230404.

It is not a weakly prime, because it can be changed into another prime (145402234433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72701115216 + 72701115217.

It is an arithmetic number, because the mean of its divisors is an integer number (72701115217).

Almost surely, 2145402230433 is an apocalyptic number.

It is an amenable number.

145402230433 is a deficient number, since it is larger than the sum of its proper divisors (1).

145402230433 is an equidigital number, since it uses as much as digits as its factorization.

145402230433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 145402230433 its reverse (334032204541), we get a palindrome (479434434974).

The spelling of 145402230433 in words is "one hundred forty-five billion, four hundred two million, two hundred thirty thousand, four hundred thirty-three".