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145404100132 = 2236351025033
BaseRepresentation
bin1000011101101011000…
…0100111111000100100
3111220022110110121110221
42013122300213320210
54340241422201012
6150444150254124
713335151313164
oct2073260477044
9456273417427
10145404100132
11567359075a5
122421b657344
1310933369495
1470752405a4
153bb039b507
hex21dac27e24

145404100132 has 6 divisors (see below), whose sum is σ = 254457175238. Its totient is φ = 72702050064.

The previous prime is 145404100117. The next prime is 145404100159. The reversal of 145404100132 is 231001404541.

It can be written as a sum of positive squares in only one way, i.e., 145394265636 + 9834496 = 381306^2 + 3136^2 .

It is a super-2 number, since 2×1454041001322 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145404100097 and 145404100106.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 18175512513 + ... + 18175512520.

Almost surely, 2145404100132 is an apocalyptic number.

It is an amenable number.

145404100132 is a deficient number, since it is larger than the sum of its proper divisors (109053075106).

145404100132 is a wasteful number, since it uses less digits than its factorization.

145404100132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36351025037 (or 36351025035 counting only the distinct ones).

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 145404100132 its reverse (231001404541), we get a palindrome (376405504673).

The spelling of 145404100132 in words is "one hundred forty-five billion, four hundred four million, one hundred thousand, one hundred thirty-two".

Divisors: 1 2 4 36351025033 72702050066 145404100132