145404100133 has 4 divisors (see below), whose sum is σ = 150094555008. Its totient is φ = 140713645260.

The previous prime is 145404100117. The next prime is 145404100159. The reversal of 145404100133 is 331001404541.

It is a happy number.

145404100133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 331001404541 = 154027 ⋅2148983.

It is a cyclic number.

It is not a de Polignac number, because 145404100133 - 2⁴ = 145404100117 is a prime.

It is a super-2 number, since 2×145404100133² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145404100033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2345227391 + ... + 2345227452.

It is an arithmetic number, because the mean of its divisors is an integer number (37523638752).

Almost surely, 2^145404100133 is an apocalyptic number.

It is an amenable number.

145404100133 is a deficient number, since it is larger than the sum of its proper divisors (4690454875).

145404100133 is an equidigital number, since it uses as much as digits as its factorization.

145404100133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4690454874.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 145404100133 its reverse (331001404541), we get a palindrome (476405504674).

The spelling of 145404100133 in words is "one hundred forty-five billion, four hundred four million, one hundred thousand, one hundred thirty-three".