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145412223217 is a prime number
BaseRepresentation
bin1000011101101100111…
…1100111000011110001
3111220100000202022020221
42013123033213003301
54340301012120332
6150445040333041
713335310334512
oct2073317470361
9456300668227
10145412223217
115673a455598
1224222314181
1310934c51941
147076356a09
153bb0e53297
hex21db3e70f1

145412223217 has 2 divisors, whose sum is σ = 145412223218. Its totient is φ = 145412223216.

The previous prime is 145412223191. The next prime is 145412223241. The reversal of 145412223217 is 712322214541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112519322721 + 32892900496 = 335439^2 + 181364^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145412223217 is a prime.

It is a super-3 number, since 3×1454122232173 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (145412226217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72706111608 + 72706111609.

It is an arithmetic number, because the mean of its divisors is an integer number (72706111609).

Almost surely, 2145412223217 is an apocalyptic number.

It is an amenable number.

145412223217 is a deficient number, since it is larger than the sum of its proper divisors (1).

145412223217 is an equidigital number, since it uses as much as digits as its factorization.

145412223217 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 26880, while the sum is 34.

Adding to 145412223217 its reverse (712322214541), we get a palindrome (857734437758).

The spelling of 145412223217 in words is "one hundred forty-five billion, four hundred twelve million, two hundred twenty-three thousand, two hundred seventeen".