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145430031225107 is a prime number
BaseRepresentation
bin100001000100010010010001…
…010110011101000100010011
3201001220222022220222100011202
4201010102101112131010103
5123030211200443200412
61233145344541101415
742426654514121336
oct4104222126350423
9631828286870152
10145430031225107
114237a591301002
121438939325786b
13631bcbaabb885
1427cabcb48c61d
1511c2e7ed4c3c2
hex84449159d113

145430031225107 has 2 divisors, whose sum is σ = 145430031225108. Its totient is φ = 145430031225106.

The previous prime is 145430031225019. The next prime is 145430031225137. The reversal of 145430031225107 is 701522130034541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145430031225107 - 214 = 145430031208723 is a prime.

It is a super-3 number, since 3×1454300312251073 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (145430031225137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72715015612553 + 72715015612554.

It is an arithmetic number, because the mean of its divisors is an integer number (72715015612554).

Almost surely, 2145430031225107 is an apocalyptic number.

145430031225107 is a deficient number, since it is larger than the sum of its proper divisors (1).

145430031225107 is an equidigital number, since it uses as much as digits as its factorization.

145430031225107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 100800, while the sum is 38.

Adding to 145430031225107 its reverse (701522130034541), we get a palindrome (846952161259648).

The spelling of 145430031225107 in words is "one hundred forty-five trillion, four hundred thirty billion, thirty-one million, two hundred twenty-five thousand, one hundred seven".