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14543201051 is a prime number
BaseRepresentation
bin11011000101101011…
…11010001100011011
31101112112121011022222
431202311322030123
5214241024413201
610403035134255
71023252112031
oct154265721433
941475534288
1014543201051
116193292225
12299a5a438b
1314aa00b812
149bd6b6551
155a1b8191b
hex362d7a31b

14543201051 has 2 divisors, whose sum is σ = 14543201052. Its totient is φ = 14543201050.

The previous prime is 14543200999. The next prime is 14543201053. The reversal of 14543201051 is 15010234541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14543201051 - 210 = 14543200027 is a prime.

Together with 14543201053, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14543201051.

It is not a weakly prime, because it can be changed into another prime (14543201053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7271600525 + 7271600526.

It is an arithmetic number, because the mean of its divisors is an integer number (7271600526).

Almost surely, 214543201051 is an apocalyptic number.

14543201051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14543201051 is an equidigital number, since it uses as much as digits as its factorization.

14543201051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 14543201051 its reverse (15010234541), we get a palindrome (29553435592).

The spelling of 14543201051 in words is "fourteen billion, five hundred forty-three million, two hundred one thousand, fifty-one".