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1454413151 is a prime number
BaseRepresentation
bin101011010110000…
…1001010101011111
310202100201211202202
41112230021111133
510434312210101
6400153042115
751020210402
oct12654112537
93670654682
101454413151
11686a84144
123470b633b
131a24207c9
14db237d39
1587a4236b
hex56b0955f

1454413151 has 2 divisors, whose sum is σ = 1454413152. Its totient is φ = 1454413150.

The previous prime is 1454413139. The next prime is 1454413171. The reversal of 1454413151 is 1513144541.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1454413151 is a prime.

It is a super-2 number, since 2×14544131512 = 4230635227603497602, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1454413111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727206575 + 727206576.

It is an arithmetic number, because the mean of its divisors is an integer number (727206576).

Almost surely, 21454413151 is an apocalyptic number.

1454413151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1454413151 is an equidigital number, since it uses as much as digits as its factorization.

1454413151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4800, while the sum is 29.

The square root of 1454413151 is about 38136.7690162657. The cubic root of 1454413151 is about 1132.9983157889.

Adding to 1454413151 its reverse (1513144541), we get a palindrome (2967557692).

The spelling of 1454413151 in words is "one billion, four hundred fifty-four million, four hundred thirteen thousand, one hundred fifty-one".