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14546661254513 is a prime number
BaseRepresentation
bin1101001110101110100010…
…0100111010010101110001
31220111122110211111222211122
43103223220210322111301
53401313030240121023
650534351030552025
73030650553346013
oct323535044722561
956448424458748
1014546661254513
1146a9228058243
12176b2a7508615
1381698a21489b
143840c27dc1b3
151a35d321d2c8
hexd3ae893a571

14546661254513 has 2 divisors, whose sum is σ = 14546661254514. Its totient is φ = 14546661254512.

The previous prime is 14546661254501. The next prime is 14546661254527. The reversal of 14546661254513 is 31545216664541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8047593101584 + 6499068152929 = 2836828^2 + 2549327^2 .

It is an emirp because it is prime and its reverse (31545216664541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14546661254513 - 214 = 14546661238129 is a prime.

It is not a weakly prime, because it can be changed into another prime (14546661254563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7273330627256 + 7273330627257.

It is an arithmetic number, because the mean of its divisors is an integer number (7273330627257).

Almost surely, 214546661254513 is an apocalyptic number.

It is an amenable number.

14546661254513 is a deficient number, since it is larger than the sum of its proper divisors (1).

14546661254513 is an equidigital number, since it uses as much as digits as its factorization.

14546661254513 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10368000, while the sum is 53.

The spelling of 14546661254513 in words is "fourteen trillion, five hundred forty-six billion, six hundred sixty-one million, two hundred fifty-four thousand, five hundred thirteen".