Base | Representation |
---|---|
bin | 1101001110111100111010… |
… | …1001110111111101100011 |
3 | 1220112000102211220101121012 |
4 | 3103233032221313331203 |
5 | 3401343431424041141 |
6 | 50540230041251135 |
7 | 3031145324334122 |
oct | 323571651677543 |
9 | 56460384811535 |
10 | 14550521315171 |
11 | 46aa928a50a16 |
12 | 176bba4193aab |
13 | 817153b4a74a |
14 | 38436b325ab9 |
15 | 1a375c04eceb |
hex | d3bcea77f63 |
14550521315171 has 2 divisors, whose sum is σ = 14550521315172. Its totient is φ = 14550521315170.
The previous prime is 14550521315111. The next prime is 14550521315173. The reversal of 14550521315171 is 17151312505541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14550521315171 - 26 = 14550521315107 is a prime.
Together with 14550521315173, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14550521315173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7275260657585 + 7275260657586.
It is an arithmetic number, because the mean of its divisors is an integer number (7275260657586).
Almost surely, 214550521315171 is an apocalyptic number.
14550521315171 is a deficient number, since it is larger than the sum of its proper divisors (1).
14550521315171 is an equidigital number, since it uses as much as digits as its factorization.
14550521315171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 105000, while the sum is 41.
The spelling of 14550521315171 in words is "fourteen trillion, five hundred fifty billion, five hundred twenty-one million, three hundred fifteen thousand, one hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •