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14550521315171 is a prime number
BaseRepresentation
bin1101001110111100111010…
…1001110111111101100011
31220112000102211220101121012
43103233032221313331203
53401343431424041141
650540230041251135
73031145324334122
oct323571651677543
956460384811535
1014550521315171
1146aa928a50a16
12176bba4193aab
13817153b4a74a
1438436b325ab9
151a375c04eceb
hexd3bcea77f63

14550521315171 has 2 divisors, whose sum is σ = 14550521315172. Its totient is φ = 14550521315170.

The previous prime is 14550521315111. The next prime is 14550521315173. The reversal of 14550521315171 is 17151312505541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14550521315171 - 26 = 14550521315107 is a prime.

Together with 14550521315173, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14550521315173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7275260657585 + 7275260657586.

It is an arithmetic number, because the mean of its divisors is an integer number (7275260657586).

Almost surely, 214550521315171 is an apocalyptic number.

14550521315171 is a deficient number, since it is larger than the sum of its proper divisors (1).

14550521315171 is an equidigital number, since it uses as much as digits as its factorization.

14550521315171 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 105000, while the sum is 41.

The spelling of 14550521315171 in words is "fourteen trillion, five hundred fifty billion, five hundred twenty-one million, three hundred fifteen thousand, one hundred seventy-one".