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14552334125149 is a prime number
BaseRepresentation
bin1101001111000011101010…
…1101001100100001011101
31220112012010012000200101111
43103300322231030201131
53401411140014001044
650541130000142021
73031241256063322
oct323607255144135
956465105020344
1014552334125149
114700679264987
12177040b307911
138173825a4382
1438449ddb4b49
151a3816288b34
hexd3c3ab4c85d

14552334125149 has 2 divisors, whose sum is σ = 14552334125150. Its totient is φ = 14552334125148.

The previous prime is 14552334125143. The next prime is 14552334125167. The reversal of 14552334125149 is 94152143325541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12811438600249 + 1740895524900 = 3579307^2 + 1319430^2 .

It is a cyclic number.

It is not a de Polignac number, because 14552334125149 - 23 = 14552334125141 is a prime.

It is a super-2 number, since 2×145523341251492 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14552334125141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7276167062574 + 7276167062575.

It is an arithmetic number, because the mean of its divisors is an integer number (7276167062575).

Almost surely, 214552334125149 is an apocalyptic number.

It is an amenable number.

14552334125149 is a deficient number, since it is larger than the sum of its proper divisors (1).

14552334125149 is an equidigital number, since it uses as much as digits as its factorization.

14552334125149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592000, while the sum is 49.

The spelling of 14552334125149 in words is "fourteen trillion, five hundred fifty-two billion, three hundred thirty-four million, one hundred twenty-five thousand, one hundred forty-nine".