Base | Representation |
---|---|
bin | 100001000101101001111001… |
… | …100011001110011100010000 |
3 | 201002020222012012212022122111 |
4 | 201011221321203032130100 |
5 | 123033231400011403100 |
6 | 1233300505223515104 |
7 | 42436525245532165 |
oct | 4105517143163420 |
9 | 632228165768574 |
10 | 145524121200400 |
11 | 42406484680068 |
12 | 143a36718b8a94 |
13 | 6327b34076177 |
14 | 27d159564206c |
15 | 11c563a2c36ba |
hex | 845a798ce710 |
145524121200400 has 60 divisors (see below), whose sum is σ = 349648404490000. Its totient is φ = 58205202560640.
The previous prime is 145524121200361. The next prime is 145524121200431. The reversal of 145524121200400 is 4002121425541.
It is a super-2 number, since 2×1455241212004002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8647350 + ... + 19126549.
Almost surely, 2145524121200400 is an apocalyptic number.
145524121200400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
145524121200400 is an abundant number, since it is smaller than the sum of its proper divisors (204124283289600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
145524121200400 is a wasteful number, since it uses less digits than its factorization.
145524121200400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27787016 (or 27787005 counting only the distinct ones).
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 145524121200400 its reverse (4002121425541), we get a palindrome (149526242625941).
The spelling of 145524121200400 in words is "one hundred forty-five trillion, five hundred twenty-four billion, one hundred twenty-one million, two hundred thousand, four hundred".
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