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145534065143 is a prime number
BaseRepresentation
bin1000011110001010000…
…0011001100111110111
3111220122112000111221212
42013202200121213313
54341023210041033
6150505112032035
713341320100005
oct2074240314767
9456575014855
10145534065143
11567a22051a5
122425709261b
131095427205c
1470885d1a75
153bbb9be748
hex21e28199f7

145534065143 has 2 divisors, whose sum is σ = 145534065144. Its totient is φ = 145534065142.

The previous prime is 145534065133. The next prime is 145534065161. The reversal of 145534065143 is 341560435541.

145534065143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 145534065143 - 210 = 145534064119 is a prime.

It is a super-3 number, since 3×1455340651433 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 145534065143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145534065133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72767032571 + 72767032572.

It is an arithmetic number, because the mean of its divisors is an integer number (72767032572).

Almost surely, 2145534065143 is an apocalyptic number.

145534065143 is a deficient number, since it is larger than the sum of its proper divisors (1).

145534065143 is an equidigital number, since it uses as much as digits as its factorization.

145534065143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 41.

The spelling of 145534065143 in words is "one hundred forty-five billion, five hundred thirty-four million, sixty-five thousand, one hundred forty-three".