Base | Representation |
---|---|
bin | 10101001011011110000… |
… | …010110001100001011011 |
3 | 12011010201000102122102102 |
4 | 111023132002301201123 |
5 | 142321202044341011 |
6 | 3032340155554015 |
7 | 210102524465045 |
oct | 25133602614133 |
9 | 5133630378372 |
10 | 1455424215131 |
11 | 511273032467 |
12 | 1b60a275b90b |
13 | a7327374943 |
14 | 5062b4a6a95 |
15 | 27cd3d0473b |
hex | 152de0b185b |
1455424215131 has 2 divisors, whose sum is σ = 1455424215132. Its totient is φ = 1455424215130.
The previous prime is 1455424215109. The next prime is 1455424215137. The reversal of 1455424215131 is 1315124245541.
It is a strong prime.
It is an emirp because it is prime and its reverse (1315124245541) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1455424215131 is a prime.
It is a super-2 number, since 2×14554242151312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1455424215137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727712107565 + 727712107566.
It is an arithmetic number, because the mean of its divisors is an integer number (727712107566).
Almost surely, 21455424215131 is an apocalyptic number.
1455424215131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1455424215131 is an equidigital number, since it uses as much as digits as its factorization.
1455424215131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 96000, while the sum is 38.
The spelling of 1455424215131 in words is "one trillion, four hundred fifty-five billion, four hundred twenty-four million, two hundred fifteen thousand, one hundred thirty-one".
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