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1455700133441 is a prime number
BaseRepresentation
bin10101001011101110011…
…111010100011001000001
312011011102020121202012002
4111023232133110121001
5142322233213232231
63032423413513345
7210112414655441
oct25135637243101
95134366552162
101455700133441
115113a4858a24
121b615b042855
13a736c590508
1450655dac121
1527ced1580cb
hex152ee7d4641

1455700133441 has 2 divisors, whose sum is σ = 1455700133442. Its totient is φ = 1455700133440.

The previous prime is 1455700133417. The next prime is 1455700133449. The reversal of 1455700133441 is 1443310075541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1058048818225 + 397651315216 = 1028615^2 + 630596^2 .

It is a cyclic number.

It is not a de Polignac number, because 1455700133441 - 214 = 1455700117057 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1455700133395 and 1455700133404.

It is not a weakly prime, because it can be changed into another prime (1455700133449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727850066720 + 727850066721.

It is an arithmetic number, because the mean of its divisors is an integer number (727850066721).

Almost surely, 21455700133441 is an apocalyptic number.

It is an amenable number.

1455700133441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1455700133441 is an equidigital number, since it uses as much as digits as its factorization.

1455700133441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 38.

The spelling of 1455700133441 in words is "one trillion, four hundred fifty-five billion, seven hundred million, one hundred thirty-three thousand, four hundred forty-one".