Base | Representation |
---|---|
bin | 10101001100001111100… |
… | …000001011010101100111 |
3 | 12011012211211211102100221 |
4 | 111030033200023111213 |
5 | 142324402011203011 |
6 | 3032554401145211 |
7 | 210132221551204 |
oct | 25141740132547 |
9 | 5135754742327 |
10 | 1456254006631 |
11 | 511659471066 |
12 | 1b629462b207 |
13 | a742a258928 |
14 | 506a9788cab |
15 | 27d31ab3971 |
hex | 1530f80b567 |
1456254006631 has 2 divisors, whose sum is σ = 1456254006632. Its totient is φ = 1456254006630.
The previous prime is 1456254006611. The next prime is 1456254006643. The reversal of 1456254006631 is 1366004526541.
It is a strong prime.
It is an emirp because it is prime and its reverse (1366004526541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1456254006631 - 213 = 1456253998439 is a prime.
It is a super-2 number, since 2×14562540066312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1456254006611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 728127003315 + 728127003316.
It is an arithmetic number, because the mean of its divisors is an integer number (728127003316).
Almost surely, 21456254006631 is an apocalyptic number.
1456254006631 is a deficient number, since it is larger than the sum of its proper divisors (1).
1456254006631 is an equidigital number, since it uses as much as digits as its factorization.
1456254006631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 43.
The spelling of 1456254006631 in words is "one trillion, four hundred fifty-six billion, two hundred fifty-four million, six thousand, six hundred thirty-one".
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