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14572020143 is a prime number
BaseRepresentation
bin11011001001000111…
…10110000110101111
31101121112211022200202
431210203312012233
5214320414121033
610405544544115
71024052061512
oct154443660657
941545738622
1014572020143
1161a858645a
1229a818203b
1314b2c8c135
149c3458d79
155a44758e8
hex3648f61af

14572020143 has 2 divisors, whose sum is σ = 14572020144. Its totient is φ = 14572020142.

The previous prime is 14572020121. The next prime is 14572020149. The reversal of 14572020143 is 34102027541.

It is a strong prime.

It is an emirp because it is prime and its reverse (34102027541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14572020143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14572020149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7286010071 + 7286010072.

It is an arithmetic number, because the mean of its divisors is an integer number (7286010072).

Almost surely, 214572020143 is an apocalyptic number.

14572020143 is a deficient number, since it is larger than the sum of its proper divisors (1).

14572020143 is an equidigital number, since it uses as much as digits as its factorization.

14572020143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 29.

Adding to 14572020143 its reverse (34102027541), we get a palindrome (48674047684).

The spelling of 14572020143 in words is "fourteen billion, five hundred seventy-two million, twenty thousand, one hundred forty-three".