14580113441 has 2 divisors, whose sum is σ = 14580113442. Its totient is φ = 14580113440.

The previous prime is 14580113389. The next prime is 14580113447. The reversal of 14580113441 is 14431108541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14573559841 + 6553600 = 120721^2 + 2560^2 .

It is an emirp because it is prime and its reverse (14431108541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14580113441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14580113398 and 14580113407.

It is not a weakly prime, because it can be changed into another prime (14580113447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7290056720 + 7290056721.

It is an arithmetic number, because the mean of its divisors is an integer number (7290056721).

Almost surely, 2^14580113441 is an apocalyptic number.

It is an amenable number.

14580113441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14580113441 is an equidigital number, since it uses as much as digits as its factorization.

14580113441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7680, while the sum is 32.

The spelling of 14580113441 in words is "fourteen billion, five hundred eighty million, one hundred thirteen thousand, four hundred forty-one".