Base | Representation |
---|---|
bin | 1101010010000010101111… |
… | …1110000000010111011101 |
3 | 1220201002111211122100010012 |
4 | 3110200223332000113131 |
5 | 3403231211334343432 |
6 | 51020451405253005 |
7 | 3035035322651612 |
oct | 324405376002735 |
9 | 56632454570105 |
10 | 14603626481117 |
11 | 47203aa484113 |
12 | 177a344b64165 |
13 | 81c16800396b |
14 | 386b681d6509 |
15 | 1a4d1930dcb2 |
hex | d482bf805dd |
14603626481117 has 2 divisors, whose sum is σ = 14603626481118. Its totient is φ = 14603626481116.
The previous prime is 14603626481077. The next prime is 14603626481243. The reversal of 14603626481117 is 71118462630641.
14603626481117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12682245153796 + 1921381327321 = 3561214^2 + 1386139^2 .
It is a cyclic number.
It is not a de Polignac number, because 14603626481117 - 220 = 14603625432541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14603626487117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7301813240558 + 7301813240559.
It is an arithmetic number, because the mean of its divisors is an integer number (7301813240559).
Almost surely, 214603626481117 is an apocalyptic number.
It is an amenable number.
14603626481117 is a deficient number, since it is larger than the sum of its proper divisors (1).
14603626481117 is an equidigital number, since it uses as much as digits as its factorization.
14603626481117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1161216, while the sum is 50.
The spelling of 14603626481117 in words is "fourteen trillion, six hundred three billion, six hundred twenty-six million, four hundred eighty-one thousand, one hundred seventeen".
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