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14627113841 is a prime number
BaseRepresentation
bin11011001111101100…
…00000101101110001
31101202101111101001002
431213312000231301
5214424020120331
610415233451345
71025321262524
oct154766005561
941671441032
1014627113841
11622669613a
122a02710b55
1314c150bb62
149ca8babbb
155a92099cb
hex367d80b71

14627113841 has 2 divisors, whose sum is σ = 14627113842. Its totient is φ = 14627113840.

The previous prime is 14627113759. The next prime is 14627113889. The reversal of 14627113841 is 14831172641.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10314433600 + 4312680241 = 101560^2 + 65671^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14627113841 is a prime.

It is a super-3 number, since 3×146271138413 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14627113795 and 14627113804.

It is not a weakly prime, because it can be changed into another prime (14627116841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7313556920 + 7313556921.

It is an arithmetic number, because the mean of its divisors is an integer number (7313556921).

Almost surely, 214627113841 is an apocalyptic number.

It is an amenable number.

14627113841 is a deficient number, since it is larger than the sum of its proper divisors (1).

14627113841 is an equidigital number, since it uses as much as digits as its factorization.

14627113841 is an evil number, because the sum of its binary digits is even.

The product of its digits is 32256, while the sum is 38.

The spelling of 14627113841 in words is "fourteen billion, six hundred twenty-seven million, one hundred thirteen thousand, eight hundred forty-one".