Base | Representation |
---|---|
bin | 100001010001001000111111… |
… | …101011101001110100101111 |
3 | 201012001102112002220220121021 |
4 | 201101020333223221310233 |
5 | 123134144343111014042 |
6 | 1235103243104515011 |
7 | 42550540023355363 |
oct | 4121107753516457 |
9 | 635042462826537 |
10 | 146313424313647 |
11 | 426901a1707488 |
12 | 144b063191ba67 |
13 | 63843b1b46046 |
14 | 281b87107b2a3 |
15 | 11dae3444c867 |
hex | 85123fae9d2f |
146313424313647 has 2 divisors, whose sum is σ = 146313424313648. Its totient is φ = 146313424313646.
The previous prime is 146313424313611. The next prime is 146313424313689. The reversal of 146313424313647 is 746313424313641.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 146313424313647 - 211 = 146313424311599 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 146313424313594 and 146313424313603.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (146313424314647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73156712156823 + 73156712156824.
It is an arithmetic number, because the mean of its divisors is an integer number (73156712156824).
Almost surely, 2146313424313647 is an apocalyptic number.
146313424313647 is a deficient number, since it is larger than the sum of its proper divisors (1).
146313424313647 is an equidigital number, since it uses as much as digits as its factorization.
146313424313647 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10450944, while the sum is 52.
The spelling of 146313424313647 in words is "one hundred forty-six trillion, three hundred thirteen billion, four hundred twenty-four million, three hundred thirteen thousand, six hundred forty-seven".
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