Base | Representation |
---|---|
bin | 11011010000010010… |
… | …01001111010011011 |
3 | 1101202201221100000010 |
4 | 31220021021322123 |
5 | 214431311213001 |
6 | 10415533213003 |
7 | 1025412033462 |
oct | 155011117233 |
9 | 41681840003 |
10 | 14632132251 |
11 | 6229503590 |
12 | 2a04331163 |
13 | 14c2578129 |
14 | 9cb4259d9 |
15 | 5a989b8d6 |
hex | 368249e9b |
14632132251 has 32 divisors (see below), whose sum is σ = 21795257088. Its totient is φ = 8656269440.
The previous prime is 14632132243. The next prime is 14632132253. The reversal of 14632132251 is 15223123641.
14632132251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 14632132251 - 23 = 14632132243 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14632132253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 323320 + ... + 365786.
It is an arithmetic number, because the mean of its divisors is an integer number (681101784).
Almost surely, 214632132251 is an apocalyptic number.
14632132251 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14632132251 is a deficient number, since it is larger than the sum of its proper divisors (7163124837).
14632132251 is a wasteful number, since it uses less digits than its factorization.
14632132251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42731.
The product of its digits is 8640, while the sum is 30.
Adding to 14632132251 its reverse (15223123641), we get a palindrome (29855255892).
The spelling of 14632132251 in words is "fourteen billion, six hundred thirty-two million, one hundred thirty-two thousand, two hundred fifty-one".
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