Base | Representation |
---|---|
bin | 1101010100001011000101… |
… | …0011111000011111011111 |
3 | 1220211120222100001120212012 |
4 | 3111002301103320133133 |
5 | 3404331134132333002 |
6 | 51045343054501435 |
7 | 3040502244666122 |
oct | 325026123703737 |
9 | 56746870046765 |
10 | 14640223324127 |
11 | 473497a43aa15 |
12 | 178545920487b |
13 | 82274acc645b |
14 | 38883a8143b9 |
15 | 1a5c5c167d52 |
hex | d50b14f87df |
14640223324127 has 2 divisors, whose sum is σ = 14640223324128. Its totient is φ = 14640223324126.
The previous prime is 14640223324093. The next prime is 14640223324157. The reversal of 14640223324127 is 72142332204641.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14640223324127 - 226 = 14640156215263 is a prime.
It is a super-2 number, since 2×146402233241272 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14640223324157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7320111662063 + 7320111662064.
It is an arithmetic number, because the mean of its divisors is an integer number (7320111662064).
Almost surely, 214640223324127 is an apocalyptic number.
14640223324127 is a deficient number, since it is larger than the sum of its proper divisors (1).
14640223324127 is an equidigital number, since it uses as much as digits as its factorization.
14640223324127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 41.
Adding to 14640223324127 its reverse (72142332204641), we get a palindrome (86782555528768).
The spelling of 14640223324127 in words is "fourteen trillion, six hundred forty billion, two hundred twenty-three million, three hundred twenty-four thousand, one hundred twenty-seven".
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