Base | Representation |
---|---|
bin | 10101010011101011101… |
… | …000000000010001000101 |
3 | 12011222110112200012110001 |
4 | 111103223220000101011 |
5 | 142442231423411003 |
6 | 3040355152001301 |
7 | 210534165520225 |
oct | 25235350002105 |
9 | 5158415605401 |
10 | 1464242013253 |
11 | 514a88497728 |
12 | 1b7943830231 |
13 | a810115ca76 |
14 | 50c26610085 |
15 | 2814cee061d |
hex | 154eba00445 |
1464242013253 has 2 divisors, whose sum is σ = 1464242013254. Its totient is φ = 1464242013252.
The previous prime is 1464242013209. The next prime is 1464242013277. The reversal of 1464242013253 is 3523102424641.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1193615245729 + 270626767524 = 1092527^2 + 520218^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1464242013253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1464242013203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 732121006626 + 732121006627.
It is an arithmetic number, because the mean of its divisors is an integer number (732121006627).
Almost surely, 21464242013253 is an apocalyptic number.
It is an amenable number.
1464242013253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1464242013253 is an equidigital number, since it uses as much as digits as its factorization.
1464242013253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 1464242013253 its reverse (3523102424641), we get a palindrome (4987344437894).
The spelling of 1464242013253 in words is "one trillion, four hundred sixty-four billion, two hundred forty-two million, thirteen thousand, two hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •