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1465231743397 is a prime number
BaseRepresentation
bin10101010100100110100…
…111100001100110100101
312012002000112000200222001
4111110212213201212211
5143001243311242042
63041041305205301
7210600544215652
oct25244647414645
95162015020861
101465231743397
11515446136624
121b7b7b190831
13a822b2125c6
1450cbbc46c29
15281a9d43bb7
hex155269e19a5

1465231743397 has 2 divisors, whose sum is σ = 1465231743398. Its totient is φ = 1465231743396.

The previous prime is 1465231743383. The next prime is 1465231743463. The reversal of 1465231743397 is 7933471325641.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 846352160676 + 618879582721 = 919974^2 + 786689^2 .

It is an emirp because it is prime and its reverse (7933471325641) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1465231743397 is a prime.

It is a super-3 number, since 3×14652317433973 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1465531743397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 732615871698 + 732615871699.

It is an arithmetic number, because the mean of its divisors is an integer number (732615871699).

Almost surely, 21465231743397 is an apocalyptic number.

It is an amenable number.

1465231743397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1465231743397 is an equidigital number, since it uses as much as digits as its factorization.

1465231743397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11430720, while the sum is 55.

The spelling of 1465231743397 in words is "one trillion, four hundred sixty-five billion, two hundred thirty-one million, seven hundred forty-three thousand, three hundred ninety-seven".