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14664984913 is a prime number
BaseRepresentation
bin11011010100001100…
…11110100101010001
31101212000202102101101
431222012132211101
5220013214004123
610423105304401
71026261213025
oct155206364521
941760672341
1014664984913
116246002247
122a13335101
1314c930b687
149d1938385
155ac6daaad
hex36a19e951

14664984913 has 2 divisors, whose sum is σ = 14664984914. Its totient is φ = 14664984912.

The previous prime is 14664984911. The next prime is 14664984949. The reversal of 14664984913 is 31948946641.

14664984913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14628418704 + 36566209 = 120948^2 + 6047^2 .

It is a cyclic number.

It is not a de Polignac number, because 14664984913 - 21 = 14664984911 is a prime.

It is a super-3 number, since 3×146649849133 (a number of 31 digits) contains 333 as substring.

Together with 14664984911, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14664984911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7332492456 + 7332492457.

It is an arithmetic number, because the mean of its divisors is an integer number (7332492457).

Almost surely, 214664984913 is an apocalyptic number.

It is an amenable number.

14664984913 is a deficient number, since it is larger than the sum of its proper divisors (1).

14664984913 is an equidigital number, since it uses as much as digits as its factorization.

14664984913 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4478976, while the sum is 55.

The spelling of 14664984913 in words is "fourteen billion, six hundred sixty-four million, nine hundred eighty-four thousand, nine hundred thirteen".