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14665064996773 is a prime number
BaseRepresentation
bin1101010101100111100111…
…1111010101111110100101
31220220222002121001022101001
43111121321333111332211
53410233023114344043
651105012102033301
73042341660505532
oct325317177257645
956828077038331
1014665064996773
114744467967294
12178a230718831
13824ba97a6639
14389b15b45d89
151a6712eb374d
hexd5679fd5fa5

14665064996773 has 2 divisors, whose sum is σ = 14665064996774. Its totient is φ = 14665064996772.

The previous prime is 14665064996693. The next prime is 14665064996779. The reversal of 14665064996773 is 37769946056641.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8402768955009 + 6262296041764 = 2898753^2 + 2502458^2 .

It is a cyclic number.

It is not a de Polignac number, because 14665064996773 - 221 = 14665062899621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14665064996696 and 14665064996705.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14665064996779) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7332532498386 + 7332532498387.

It is an arithmetic number, because the mean of its divisors is an integer number (7332532498387).

Almost surely, 214665064996773 is an apocalyptic number.

It is an amenable number.

14665064996773 is a deficient number, since it is larger than the sum of its proper divisors (1).

14665064996773 is an equidigital number, since it uses as much as digits as its factorization.

14665064996773 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1234517760, while the sum is 73.

The spelling of 14665064996773 in words is "fourteen trillion, six hundred sixty-five billion, sixty-four million, nine hundred ninety-six thousand, seven hundred seventy-three".