Base | Representation |
---|---|
bin | 1101010110100001101101… |
… | …0010000101010111010111 |
3 | 1220222110100011011110001121 |
4 | 3111220123102011113113 |
5 | 3411011440410140002 |
6 | 51120111130104411 |
7 | 3043433224405606 |
oct | 325503322052727 |
9 | 56873304143047 |
10 | 14680655943127 |
11 | 4750038613019 |
12 | 1791261b7b107 |
13 | 8264c289b395 |
14 | 38a794637a3d |
15 | 1a6d26b08237 |
hex | d5a1b4855d7 |
14680655943127 has 2 divisors, whose sum is σ = 14680655943128. Its totient is φ = 14680655943126.
The previous prime is 14680655943097. The next prime is 14680655943193. The reversal of 14680655943127 is 72134955608641.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14680655943127 - 211 = 14680655941079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14680655943227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7340327971563 + 7340327971564.
It is an arithmetic number, because the mean of its divisors is an integer number (7340327971564).
It is a 1-persistent number, because it is pandigital, but 2⋅14680655943127 = 29361311886254 is not.
Almost surely, 214680655943127 is an apocalyptic number.
14680655943127 is a deficient number, since it is larger than the sum of its proper divisors (1).
14680655943127 is an equidigital number, since it uses as much as digits as its factorization.
14680655943127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43545600, while the sum is 61.
The spelling of 14680655943127 in words is "fourteen trillion, six hundred eighty billion, six hundred fifty-five million, nine hundred forty-three thousand, one hundred twenty-seven".
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